Minimum Number of Days to Make m Bouquets
Time complexity: $O(n\log M)$
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#include <iostream>
#include <vector>
class Solution {
public:
int minDays(std::vector<int>& bloomDay, int m, int k) {
int n = bloomDay.size();
if ((long long)m * k > n) {
return -1;
}
int left = 1, right = 0;
for (int d : bloomDay) {
right = std::max(right, d);
}
for (int t = (left + right) / 2; right > left;) {
if (check(bloomDay, k, m, t)) {
right = t;
}
else {
left = t + 1;
}
t = (left + right) / 2;
}
return left;
}
private:
bool check(std::vector<int>& bloomDay, int k, int m, int t) {
int cur = 0;
for (int d : bloomDay) {
if (d <= t) {
++cur;
}
else {
cur = 0;
}
if (cur == k) {
--m;
if (m == 0) {
return true;
}
cur = 0;
}
}
return false;
}
};
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