Minimum Limit of Balls in a Bag
Time complexity: $O(n\log M)$
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#include <iostream>
#include <vector>
class Solution {
public:
int minimumSize(std::vector<int>& nums, int maxOperations) {
int left = 1, right = 0;
for (int n : nums) {
right = std::max(n, right);
}
for (int mid = (left + right) / 2; right >= left;) {
if (check(nums, maxOperations, mid)) {
right = mid - 1;
}
else {
left = mid + 1;
}
mid = (left + right) / 2;
}
return left;
}
private:
bool check(std::vector<int>& nums, int maxOperations, int num) {
for (int n : nums) {
maxOperations -= (n - 1) / num;
if (maxOperations < 0) {
return false;
}
}
return true;
}
};
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