Leetcode-1937

Maximum Number of Points with Cost

Time complexity: $O(n)$

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#include <iostream>
#include <vector>

class Solution {
public:
    long long maxPoints(vector<vector<int>>& points) {
        int m = points.size();
        int n = points[0].size();
        std::vector<long long> dp(n);
        std::vector<long long> tmp(n);
        
        long long maxe;
        for (int i = 0; i < m; ++i) {
            std::swap(tmp, dp);
            maxe = 0x8000'0000'0000'0000;
            for (int j = 0; j < n; ++j) {
                maxe = std::max(maxe, tmp[j] + j);
                dp[j] = std::max(dp[j], maxe + points[i][j] - j);
            }
            maxe = 0x8000'0000'0000'0000;
            for (int j = n - 1; j >= 0; --j) {
                maxe = std::max(maxe, tmp[j] - j);
                dp[j] = std::max(dp[j], maxe + points[i][j] + j);
            }
        }
        
        long long max_score = 0;
        for (long long i : dp) {
            max_score = std::max(max_score, i);
        }
        return max_score;
    }
};

Leetcode-1937

Licensed under CC BY-NC-SA 4.0