Leetcode-2064

Minimized Maximum of Products Distributed to Any Store

Time complexity: $O(m\log N)$

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#include <iostream>
#include <vector>

class Solution {
public:
    int minimizedMaximum(int n, std::vector<int>& quantities) {
        int m = quantities.size();
        int left = 1, right = 0;
        for (int i : quantities) {
            right = std::max(right, i);
        }
        
        n -= m;
        if (n == 0) {
            return right;
        }
        
        for (int mid = (left + right) / 2; right >= left;) {
            if (check(mid, n, quantities)) {
                right = mid - 1;
            }
            else {
                left = mid + 1;
            }
            mid = (left + right) / 2;
        }
        
        return left;
    }
    
private:
    bool check(int x, int n, std::vector<int>& quantities) {
        for (int i : quantities) {
            n -= (i - 1) / x;
            if (n < 0) {
                return false;
            }
        }
        return true;
    }
};

Leetcode-2064