Maximum Candies Allocated to K Children
Time complexity: $O(n\log M)$
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#include <iostream>
#include <vector>
class Solution {
public:
int maximumCandies(std::vector<int>& candies, long long k) {
int left = 1, right = 0;
for (int c : candies) {
right = std::max(right, c);
}
for (int mid = (left + right) / 2; right >= left;) {
if (check(candies, k, mid)) {
left = mid + 1;
}
else {
right = mid - 1;
}
mid = (left + right) / 2;
}
if (check(candies, k, left)) {
return left;
}
return right;
}
private:
bool check(std::vector<int>& candies, long long k, int num) {
for (int c : candies) {
k -= c / num;
}
return k <= 0;
}
};
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