Time complexity: $O(n\log M)$
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#include <iostream>
#include <vector>
class Solution {
public:
int minCapability(std::vector<int>& nums, int k) {
int left = 0x3fff'ffff, right = 0;
for (int n : nums) {
left = std::min(left, n);
right = std::max(right, n);
}
for (int mid = (left + right) / 2; right >= left; ) {
if (check(nums, k, mid)) {
right = mid - 1;
}
else {
left = mid + 1;
}
mid = (right + left) / 2;
}
return left;
}
private:
bool check(std::vector<int>& nums, int k, int max_num) {
int last = false;
for (int n : nums) {
if (last || n > max_num) {
last = false;
}
else {
last = true;
--k;
if (k == 0) {
return true;
}
}
}
return false;
}
};
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