Minimum Time to Repair Cars
Time complexity: $O(n\log M)$
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
|
#include <iostream>
#include <vector>
#include <cmath>
class Solution {
public:
long long repairCars(std::vector<int>& ranks, int cars) {
int n = ranks.size();
long long left = 1, right = 0x3fff'ffff;
for (long long r : ranks) {
right = std::min(right, r);
}
right *= (long long)cars * cars;
for (long long mid = (left + right); right > left;) {
if (check(ranks, cars, mid)) {
right = mid;
}
else {
left = mid + 1;
}
mid = (left + right) / 2;
}
return left;
}
private:
bool check(std::vector<int>& ranks, int cars, long long time) {
for (int r : ranks) {
cars -= (int)std::sqrt(time / r);
if (cars <= 0) {
return true;
}
}
return false;
}
};
|
