Leetcode-718

Maximum Length of Repeated Subarray

Time complexity: $O(mn)$

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#include <iostream>
#include <vector>
#include <algorithm>

class Solution {
public:
    int findLength(std::vector<int>& nums1, std::vector<int>& nums2) {
        int m = nums1.size();
        int n = nums2.size();
        if (m < n) {
            std::swap(nums1, nums2);
            std::swap(m, n);
        }
        std::vector<int> dp(n + 1, 0);
        int res = 0;
        
        for (int num : nums1) {
            for (int i = n; i > 0; --i) {
                if (nums2[i -  1] == num) {
                    dp[i] = 1 + dp[i - 1];
                    res = std::max(res, dp[i]);
                }
                else {
                    dp[i] = 0;
                }
            }
        }
        
        return res;
    }
};

Leetcode-718

Licensed under CC BY-NC-SA 4.0