Time complexity: $O(n\log M)$
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#include <iostream>
#include <vector>
class Solution {
public:
int minEatingSpeed(std::vector<int>& piles, int h) {
int n = piles.size();
int left = 1, right = 0;
for (int i : piles) {
right = std::max(i, right);
}
h -= n;
if (h == 0) {
return right;
}
for (int mid = (left + right) / 2; right > left;) {
if (check(piles, h, mid)) {
right = mid;
}
else {
left = mid + 1;
}
mid = (left + right) / 2;
}
return left;
}
private:
bool check(std::vector<int> piles, int h, int speed) {
for (int i : piles) {
h -= (i - 1) / speed;
if (h < 0) {
return false;
}
}
return true;
}
};
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